WebAnswer (1 of 2): So here if you come across this types of problems when HCF and both the numbers are given then simply use this formula . ( H.C.F. * L.C.M. = product of two numbers ) So here , we have 55 and 99 and their HCF is 11 so according to formula 11* LCM = 55*99 LCM = 495 OR YOU CAN ... WebSteps to find the HCF of any given numbers; 1) Larger number/ Smaller Number 2) The divisor of the above step / Remainder 3) The divisor of step 2 / remainder. Keep doing this step till R = 0 (Zero). 4) The last step’s divisor will be HCF. The above steps can also be used to find the HCF of more than 3 numbers.
LCM Calculator - Least Common Multiple
WebMar 12, 2024 · Step 1: The first step is to use the division lemma with 99 and 6 because 99 is greater than 6 99 = 6 x 16 + 3 Step 2: Here, the reminder 6 is not 0, we must use division lemma to 3 and 6, to get 6 = 3 x 2 + 0 As you can see, the remainder is zero, so you may end the process at this point. WebFor example, 8 = 2 3 and 90 = 2 × 3 2 × 5. If you want to find the LCM and HCF in an exam, we can use prime factor form to simplify the process. Example one. Find the LCM and HCF of 18 and 30 ... fmea pharmacy
HCF of 90, 48, 99 using Euclid
WebHCF of 3 and 4 by Long Division. HCF of 3 and 4 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly. Step 1: Divide 4 (larger number) by 3 (smaller number). Step 2: Since the remainder ≠ 0, we will divide the divisor of step 1 (3) by the remainder (1). Step 3: Repeat this process until the remainder = 0. WebHCF calculator is a multiservice tool that finds the highest common factor and lowest common factor of the given numbers at the same time. It only needs one input value to … WebStep 3: We consider the new divisor 45 and the new remainder 9, and apply the division lemma to get. 45 = 9 x 5 + 0. The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 9, the HCF of 54 and 99 is 9. Notice that 9 = HCF(45,9) = HCF(54,45) = HCF(99,54) . Therefore, HCF of 54,99 using Euclid's division ... greensborough to geelong